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Review

1. Checklist of Key Concepts

Section 5.1: Free Energy

  1. Fundamental Inequality

    • Combining the First Law with the Clausius inequality dS≥δq/TdS \ge \delta q/T and the work bound δw≥−P dV\delta w \ge -P\,dV gives

    dU≤T dS−P dV,dU \le T\,dS - P\,dV,

    with equality for reversible changes. This single inequality encodes the direction of spontaneous evolution for a closed system with PVPV-only work.

  2. Extremum Principles for Thermodynamic Potentials

    • Under different experimental constraints, a particular potential is minimized at equilibrium:

      • Constant S,VS, V: dU≤0dU \le 0 ⇒ UU minimized.

      • Constant S,PS, P: dH≤0dH \le 0 ⇒ HH minimized.

      • Constant T,VT, V: dA≤0dA \le 0 ⇒ AA minimized.

      • Constant T,PT, P: dG≤0dG \le 0 ⇒ GG minimized.

    • The T,VT,V and T,PT,P cases cover the vast majority of laboratory conditions.

  3. Legendre Transforms and Natural Variables

    • Each potential is obtained from UU by a Legendre transform that swaps an extensive variable for its conjugate intensive variable, matching the natural variables to the experimentally controllable ones.

    • Summary of natural variables and equilibrium differentials:

    potentialdefinitiondifferentialnatural variables
    UU—dU=T dS−P dVdU = T\,dS - P\,dVS,VS, V
    HHU+PVU + PVdH=T dS+V dPdH = T\,dS + V\,dPS,PS, P
    AAU−TSU - TSdA=−S dT−P dVdA = -S\,dT - P\,dVT,VT, V
    GGU+PV−TSU + PV - TSdG=−S dT+V dPdG = -S\,dT + V\,dPT,PT, P
    • Defining AA and GG extends the strategy used in Section 3.3 to define HH.

  4. Conjugate Variables as Derivatives

    • At equilibrium, intensive variables are read off as slopes of a potential along its natural-variable axes. For example:

    T=(∂U∂S)V,P=−(∂U∂V)S,T = \left(\frac{\partial U}{\partial S}\right)_V,\qquad P = -\left(\frac{\partial U}{\partial V}\right)_S,

    with analogous identities for HH, AA, and GG.

  5. Euler Relation (fixed NN)

    • For a simple system with fixed composition, U(S,V)U(S,V) is homogeneous of degree 1 in its extensive arguments. Euler’s theorem gives

    U=TS−PV.U = TS - PV.
    • Allowing NN to vary adds a μN\mu N term; this will be developed when the chemical potential is introduced.

  6. Helmholtz Free Energy as a Master Potential

    • The bridge to statistical mechanics from Section 4.3 is

    A=−kBTln⁡Q.A = -k_{\mathrm B}T\ln Q.
    • Combined with dA=−S dT−P dVdA = -S\,dT - P\,dV, every equilibrium property follows by differentiation:

    S=−(∂A∂T)V,P=−(∂A∂V)T=kBT ⁣(∂ln⁡Q∂V)T,S = -\left(\frac{\partial A}{\partial T}\right)_V,\quad P = -\left(\frac{\partial A}{\partial V}\right)_T = k_{\mathrm B}T\!\left(\frac{\partial\ln Q}{\partial V}\right)_T,

    with U=A+TSU = A + TS and CV=(∂U/∂T)N,VC_V = (\partial U/\partial T)_{N,V} following in turn.

  7. Ideal Gas from AA

    • For a monatomic ideal gas, Q=VN/(N! Λ3N)Q = V^N/(N!\,\Lambda^{3N}) and Stirling’s approximation give

    A≈−NkBT ⁣[ln⁡ ⁣(VNΛ3)+1].A \approx -Nk_{\mathrm B}T\!\left[\ln\!\left(\frac{V}{N\Lambda^3}\right) + 1\right].
    • Differentiating yields the Sackur–Tetrode entropy S=NkB[ln⁡(V/NΛ3)+5/2]S = Nk_{\mathrm B}[\ln(V/N\Lambda^3) + 5/2], the equation of state PV=NkBTPV = Nk_{\mathrm B}T, and the internal energy U=32NkBTU = \tfrac{3}{2}Nk_{\mathrm B}T — all from a single function.

  8. Gibbs Free Energy and Non-PVPV Work

    • When non-PVPV work is present, the First Law gains a δwnon-PV\delta w_{\text{non-}PV} term. At constant TT and PP:

    dG∣T,P=δwnon-PV,rev.dG\big|_{T,P} = \delta w_{\text{non-}PV,\text{rev}}.
    • ΔG\Delta G measures the reversible non-PVPV work available from a process — the “useful” work beyond unavoidable PVPV work against the atmosphere. For irreversible processes, the useful work output is strictly less than ∣ΔG∣|\Delta G|.


Section 5.2: Third Law

  1. Planck’s Statement of the Third Law

    • As T→0 KT \to 0\,\mathrm{K}, the entropy of any pure crystalline substance approaches a constant. For an ideal crystal (no defects, impurities, or disorder), that constant is zero:

    S(0 K)=0(ideal crystal).S(0\,\mathrm{K}) = 0 \quad\text{(ideal crystal)}.
    • This fixes the otherwise-undetermined integration constant in ΔS=∫δqrev/T\Delta S = \int \delta q_{\mathrm{rev}}/T.

  2. Statistical-Mechanical Justification

    • From Boltzmann’s formula S=kBln⁡ΩS = k_{\mathrm B}\ln\Omega (Section 4.3), a unique ground state has Ω0=1\Omega_0 = 1, so S(0)=kBln⁡1=0S(0) = k_{\mathrm B}\ln 1 = 0. The third law is the statement that a system with a nondegenerate ground state has zero entropy at absolute zero.

  3. Residual Entropy

    • If the ground state is degenerate or the system has frozen-in disorder (Ω0>1\Omega_0 > 1), entropy approaches a nonzero constant:

    Sres=kBln⁡Ω0.S_{\mathrm{res}} = k_{\mathrm B}\ln\Omega_0.
    • This does not violate the third law: Planck’s statement says S→S \to a constant, not necessarily zero.

    • Examples:

      • Solid CO (two nearly isoenergetic orientations per molecule): Ω0=2N\Omega_0 = 2^N, giving Sres,m=Rln⁡2≈5.76 J mol−1 K−1S_{\mathrm{res,m}} = R\ln 2 \approx 5.76\ \mathrm{J\,mol^{-1}\,K^{-1}} (experiment: ≈4.6\approx 4.6, indicating partial ordering).

      • Ice (Pauling’s model with ice rules): Ω0≈(3/2)N\Omega_0 \approx (3/2)^N, giving Sres,m=Rln⁡(3/2)≈3.37 J mol−1 K−1S_{\mathrm{res,m}} = R\ln(3/2) \approx 3.37\ \mathrm{J\,mol^{-1}\,K^{-1}} (experiment: ≈3.41\approx 3.41).

  4. Heat Capacities Must Vanish as T→0T \to 0

    • For the integral S(T)=S(0)+∫0T(CP/T′) dT′S(T) = S(0) + \int_0^T (C_P/T')\,dT' to converge, CPC_P (and similarly CVC_V) must go to zero at T=0T = 0.

    • Classical equipartition gives a temperature-independent CVC_V and therefore violates the third law. Quantum statistical mechanics resolves the contradiction: the Einstein and Debye heat capacities (Section 2.6) vanish as T→0T \to 0 because vibrational modes freeze out.

  5. Unattainability of Absolute Zero (Nernst form)

    • No finite sequence of thermodynamic operations can cool a system to exactly T=0T = 0. Each successive cooling step removes less entropy than the previous one; the process converges but never reaches zero.

  6. Absolute (Third-Law) Entropies

    • With S(0)=0S(0) = 0 fixed for ideal crystals, absolute entropies are computed by integrating CP/TC_P/T from 0 to TT and adding phase-transition contributions:

    S∘(T)=∫0TCP(T′)T′ dT′+∑transitionsΔHtrsTtrs.S^\circ(T) = \int_0^T \frac{C_P(T')}{T'}\,dT' + \sum_{\text{transitions}} \frac{\Delta H_{\mathrm{trs}}}{T_{\mathrm{trs}}}.
    • Tabulated S∘(298.15 K)S^\circ(298.15\ \mathrm{K}) values (NIST WebBook, JANAF) are the basis for computing reaction entropies and Gibbs energies.


Section 5.3: Ammonia Formation

  1. Thermodynamics vs. Kinetics

    • ΔG\Delta G determines which direction is favored at equilibrium; activation barriers determine how fast equilibrium is reached. These are independent questions.

    • For N2+3 H2→2 NH3\mathrm{N_2 + 3\,H_2 \to 2\,NH_3} at 298.15 K: ΔHr∘≈−92 kJ mol−1\Delta H_r^\circ \approx -92\ \mathrm{kJ\,mol^{-1}}, ΔSr∘≈−198 J K−1 mol−1\Delta S_r^\circ \approx -198\ \mathrm{J\,K^{-1}\,mol^{-1}}, ΔGr∘≈−33 kJ mol−1\Delta G_r^\circ \approx -33\ \mathrm{kJ\,mol^{-1}}. Thermodynamically spontaneous but kinetically inert because of the N≡N\mathrm{N\equiv N} triple bond.

    • A catalyst lowers the activation barrier without changing ΔGr∘\Delta G_r^\circ or the equilibrium constant — it accelerates forward and reverse reactions equally.

  2. Temperature Effect for ΔSr∘<0\Delta S_r^\circ < 0

    • From ΔGr∘=ΔHr∘−T ΔSr∘\Delta G_r^\circ = \Delta H_r^\circ - T\,\Delta S_r^\circ, a negative ΔSr∘\Delta S_r^\circ means −T ΔSr∘>0-T\,\Delta S_r^\circ > 0 grows with TT, driving ΔGr∘\Delta G_r^\circ upward.

    • At high enough TT, ΔGr∘\Delta G_r^\circ changes sign and the reaction becomes non-spontaneous at 1 bar.

  3. Temperature Corrections to ΔH\Delta H and ΔS\Delta S

    • From constant-PP integration:

    H(Tf)−H(Ti)=∫TiTfCP dT,S(Tf)−S(Ti)=∫TiTfCPT dT.H(T_f) - H(T_i) = \int_{T_i}^{T_f} C_P\,dT,\qquad S(T_f) - S(T_i) = \int_{T_i}^{T_f} \frac{C_P}{T}\,dT.
    • With constant CPC_P: ΔH=CP ΔT\Delta H = C_P\,\Delta T and ΔS=CPln⁡(Tf/Ti)\Delta S = C_P\ln(T_f/T_i).

  4. Ideal-Gas CPC_P from Active Degrees of Freedom

    • Using ff translational + rotational degrees of freedom (rigid-rotor, no vibrations):

    CP=(f2+1)R.C_P = \left(\frac{f}{2} + 1\right)R.
    • Linear N2,H2\mathrm{N_2, H_2}: f=5f = 5, CP=72RC_P = \tfrac{7}{2}R.

    • Nonlinear NH3\mathrm{NH_3}: f=6f = 6, CP=4RC_P = 4R.

    • For the ammonia reaction: ΔCP,r=2(4R)−(7R/2)−3(7R/2)=−6R\Delta C_{P,r} = 2(4R) - (7R/2) - 3(7R/2) = -6R.

  5. Result at 500 °C

    • Applying constant-CPC_P corrections from 298.15 K to 773.15 K gives ΔHr∘(773)≈−115.6 kJ mol−1\Delta H_r^\circ(773) \approx -115.6\ \mathrm{kJ\,mol^{-1}}, ΔSr∘(773)≈−245.4 J K−1 mol−1\Delta S_r^\circ(773) \approx -245.4\ \mathrm{J\,K^{-1}\,mol^{-1}}, and

    ΔGr∘(773)≈+74.1 kJ mol−1.\Delta G_r^\circ(773) \approx +74.1\ \mathrm{kJ\,mol^{-1}}.
    • The reaction is non-spontaneous at 1 bar — the central dilemma of Haber–Bosch.

  6. Pressure Dependence of GG (Ideal Gas)

    • From dG∣T=V dPdG\big|_T = V\,dP with V=RT/PV = RT/P:

    G(T,P)−G∘(T)=RTln⁡ ⁣(PP∘).G(T, P) - G^\circ(T) = RT\ln\!\left(\frac{P}{P^\circ}\right).
    • For a reaction with stoichiometric change Δν\Delta\nu in moles of gas:

    ΔGr(T,P)≈ΔGr∘(T)+Δν RTln⁡ ⁣(PP∘).\Delta G_r(T, P) \approx \Delta G_r^\circ(T) + \Delta\nu\,RT\ln\!\left(\frac{P}{P^\circ}\right).
    • For N2+3 H2→2 NH3\mathrm{N_2 + 3\,H_2 \to 2\,NH_3}: Δν=2−4=−2\Delta\nu = 2 - 4 = -2, so increasing PP lowers ΔGr\Delta G_r (Le Châtelier: high pressure favors the side with fewer gas molecules).

  7. Restoring Spontaneity with Pressure

    • Setting ΔGr=0\Delta G_r = 0 and solving for PP:

    P=P∘exp⁡ ⁣(−ΔGr∘(T)Δν RT).P = P^\circ\exp\!\left(-\frac{\Delta G_r^\circ(T)}{\Delta\nu\,RT}\right).
    • At 500 °C: P≈320 barP \approx 320\ \mathrm{bar}. At 400 °C: P≈87 barP \approx 87\ \mathrm{bar}. The Haber–Bosch operating window (400–500 °C, 150–350 bar) is the engineering compromise predicted by these estimates.

  8. Engineering Knobs Summary

    • Catalyst: speeds up both directions; does not change ΔGr∘\Delta G_r^\circ or KK.

    • Temperature: raises rate (Arrhenius) but pushes ΔGr∘\Delta G_r^\circ upward when ΔSr∘<0\Delta S_r^\circ < 0.

    • Pressure: compensates for the temperature penalty when Δν<0\Delta\nu < 0.


2. Checklist of Most Important Equations

Below is a unified list of the major equations from Sections 5.1–5.3.

A. Fundamental Inequality

dU≤T dS−P dV.dU \le T\,dS - P\,dV.

B. Thermodynamic Potentials and Their Differentials (fixed NN, PVPV-only work)

dU=T dS−P dV,dH=T dS+V dP,dA=−S dT−P dV,dG=−S dT+V dP.\begin{aligned} dU &= T\,dS - P\,dV,\\ dH &= T\,dS + V\,dP,\\ dA &= -S\,dT - P\,dV,\\ dG &= -S\,dT + V\,dP. \end{aligned}

C. Extremum Principles (equilibrium conditions)

dU∣S,V≤0,dH∣S,P≤0,dA∣T,V≤0,dG∣T,P≤0.dU\big|_{S,V} \le 0,\quad dH\big|_{S,P} \le 0,\quad dA\big|_{T,V} \le 0,\quad dG\big|_{T,P} \le 0.

D. Helmholtz Free Energy as a Master Potential

A=−kBTln⁡Q,S=−(∂A∂T)V,P=−(∂A∂V)T.A = -k_{\mathrm B}T\ln Q,\qquad S = -\left(\frac{\partial A}{\partial T}\right)_V,\qquad P = -\left(\frac{\partial A}{\partial V}\right)_T.

E. Pressure from the Partition Function

P=kBT ⁣(∂ln⁡Q∂V)T.P = k_{\mathrm B}T\!\left(\frac{\partial\ln Q}{\partial V}\right)_T.

F. Sackur–Tetrode Entropy (monatomic ideal gas)

S=NkB ⁣[ln⁡ ⁣(VNΛ3)+52],Λ=h2πmkBT.S = Nk_{\mathrm B}\!\left[\ln\!\left(\frac{V}{N\Lambda^3}\right) + \frac{5}{2}\right],\qquad \Lambda = \frac{h}{\sqrt{2\pi m k_{\mathrm B}T}}.

G. Gibbs Free Energy and Non-PVPV Work

dG∣T,P=δwnon-PV,rev.dG\big|_{T,P} = \delta w_{\text{non-}PV,\text{rev}}.

H. Third Law

S(0 K)=0(ideal crystal),Sres=kBln⁡Ω0(degenerate ground state).S(0\,\mathrm{K}) = 0 \quad\text{(ideal crystal)},\qquad S_{\mathrm{res}} = k_{\mathrm B}\ln\Omega_0 \quad\text{(degenerate ground state)}.

I. Absolute (Third-Law) Entropy

S∘(T)=∫0TCP(T′)T′ dT′+∑transitionsΔHtrsTtrs.S^\circ(T) = \int_0^T \frac{C_P(T')}{T'}\,dT' + \sum_{\text{transitions}} \frac{\Delta H_{\mathrm{trs}}}{T_{\mathrm{trs}}}.

J. Temperature Corrections to Reaction Thermodynamics (constant CPC_P)

ΔHr∘(Tf)=ΔHr∘(Ti)+ΔCP,r(Tf−Ti),\Delta H_r^\circ(T_f) = \Delta H_r^\circ(T_i) + \Delta C_{P,r}(T_f - T_i),
ΔSr∘(Tf)=ΔSr∘(Ti)+ΔCP,rln⁡ ⁣(TfTi).\Delta S_r^\circ(T_f) = \Delta S_r^\circ(T_i) + \Delta C_{P,r}\ln\!\left(\frac{T_f}{T_i}\right).

K. Ideal-Gas Pressure Dependence of GG

G(T,P)−G∘(T)=RTln⁡ ⁣(PP∘).G(T,P) - G^\circ(T) = RT\ln\!\left(\frac{P}{P^\circ}\right).
ΔGr(T,P)≈ΔGr∘(T)+Δν RTln⁡ ⁣(PP∘).\Delta G_r(T,P) \approx \Delta G_r^\circ(T) + \Delta\nu\,RT\ln\!\left(\frac{P}{P^\circ}\right).